HyperLink auf JLabel

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WieselAc

Top Contributor
Hallo ich bau gerade einen kleinen "About Dialog"

Viel soll da nicht drin stehen, halt nur ein kleines Logo, ein OK-Knopf und ein kleiner beschreibender Text.

Und da kommt das Problem: Gibts einen "simplen" Weg auf einem JLabel einen Hyperlink zu integrieren. Ich habs mal ganz banal mit einem entsprechenden HTML-Tag probiert, der wird aber scheinbar überlesen.



Hier mein aktueller Stand:


Code:
JLabel lInfo = new JLabel(<html>
<table>\
			 <tr><td>Version:&&&</td><td>1.1.3</td></tr>\
			 <tr><td>ID: </td><td> M012345678 - 8765</td></tr></table>\
			 
(c) Copyright Bla bla bal und bla bal 2007.
All rights reserved.

\
			 <a herf=\"http://www.test.de\">http://www.test.de</a>

);
 
Das Ding heißt href und nicht herf :lol:
Sieht dann aber nur aus wie ein Link.
Logik musst du mit einem Mouselistener hinterlegen.
 
ahhhhh oh man wie blöd kann man sein ?!?!

Danke!

Logik sollte kein problem darstellen



EDIT:

Haken kommt wenn ich es implementiert habe, vorerst sind aber noch andere Baustellen offen. Pack hier dann auch den Listener code rein.



EDIT:

so hier ist das Ergebnis. Musste natürlich nicht viel selber machen, da ich hier im Forum das passende Code Schnippselchen gefunden habe:

Code:
about.link = <html><a href=\"http://www.diekellerbar.de\">http://www.diekellerbar.de</a>


Code:
        JLabel lUrl = new JLabel(PuzzelRessources.getAsString("about.link"));
        lUrl.addMouseListener(new MouseListener(){

			public void mouseClicked(MouseEvent e) {
				String url = PuzzelRessources.getAsString("about.link");
				int start= url.indexOf("<a href=\"http://");
				int ende = url.indexOf("\">");
				System.out.println(start +" " + ende+ "  " + url);
				
				if(start != -1 && ende != -1){
					System.out.println(url.substring(start+15, ende));
					Link.displayURL(url.substring(start+14, ende));
				}
			}

Code:
package puzzel;

/* Copyright (C) 2002 */
/* This class was found at: [url]http://www.javaworld.com[/url] */

import java.io.IOException;

/**
* A simple, static class to display a URL in the system browser.

*
* Under Unix, the system browser is hard-coded to be 'netscape'.
* Netscape must be in your PATH for this to work. This has been
* tested with the following platforms: AIX, HP-UX and Solaris.

*
* Under Windows, this will bring up the default browser under windows,
* usually either Netscape or Microsoft IE. The default browser is
* determined by the OS. This has been tested under Windows 95/98/NT.

*
* Examples:

*
BrowserControl.displayURL("http://www.javaworld.com")
*
BrowserControl.displayURL("file://c:\\docs\\index.html")
*
BrowserContorl.displayURL("file:///user/joe/index.html");
*

* Note - you must include the url type -- either "http://" or
* "file://".
*/
public class Link {
    // Used to identify the windows platform.
    private static final String WIN_ID = "Windows";
    // The default system browser under windows.
    private static final String WIN_PATH = "rundll32";
    // The flag to display a url.
    private static final String WIN_FLAG = "url.dll,FileProtocolHandler";
    // The default browser under unix.
    private static final String UNIX_PATH = "netscape";
    // The flag to display a url.
    private static final String UNIX_FLAG = "-remote openURL";
    /**
    * Display a file in the system browser. If you want to display a
    * file, you must include the absolute path name.
    *
    * @param url the file's url (the url must start with either "http://"
    or
    * "file://").
    */
    public static void displayURL(String url) {
        boolean windows = isWindowsPlatform();
        String cmd = null;
        try {
            if (windows) {
                // cmd = 'rundll32 url.dll,FileProtocolHandler http://...'
                cmd = WIN_PATH + " " + WIN_FLAG + " " + url;
                Runtime.getRuntime().exec(cmd);
            } else {
                // Under Unix, Netscape has to be running for the "-remote"
                // command to work. So, we try sending the command and
                // check for an exit value. If the exit command is 0,
                // it worked, otherwise we need to start the browser.
                // cmd = 'netscape -remote openURL([url]http://www.javaworld.com[/url])'
                cmd = UNIX_PATH + ' ' + UNIX_FLAG + '(' + url + ')';
                Process p = Runtime.getRuntime().exec(cmd);
                try {
                    // wait for exit code -- if it's 0, command worked,
                    // otherwise we need to start the browser up.
                    int exitCode = p.waitFor();
                    if (exitCode != 0) {
                        // Command failed, start up the browser
                        // cmd = 'netscape http://www.javaworld.com'
                        cmd = UNIX_PATH + " " + url;
                        p = Runtime.getRuntime().exec(cmd);
                    }
                } catch (InterruptedException x) {
                    System.err.println("Error bringing up browser, cmd='" + cmd + "'");
                    System.err.println("Caught: " + x);
                }
            }
        } catch (IOException x) {
            // couldn't exec browser
            System.err.println("Could not invoke browser, command=" + cmd);
            System.err.println("Caught: " + x);
        }
    }
    /**
    * Try to determine whether this application is running under Windows
    * or some other platform by examing the "os.name" property.
    *
    * @return true if this application is running under a Windows OS
    */
    public static boolean isWindowsPlatform() {
        boolean retVal = false;
        String os = System.getProperty("os.name");
        if (os != null && os.startsWith(WIN_ID)) {
            retVal = true;
        } else {
            retVal = false;
        }
        return retVal;

    }
}
 
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